(4x-x^2)^1/2=x/2

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Solution for (4x-x^2)^1/2=x/2 equation: 


x in (-oo:+oo)

((4*x-x^2)^1)/2 = x/2 // - x/2

((4*x-x^2)^1)/2-(x/2) = 0

(4*x-x^2)/2-(x/2) = 0

(4*x-x^2)/2-x/2 = 0

4*x-x^2-x = 0

3*x-x^2 = 0

3*x-x^2 = 0

x*(3-x) = 0

3-x = 0 // - 3

-x = -3 // * -1

x = 3

x*(x-3) = 0

(x*(x-3))/2 = 0

(x*(x-3))/2 = 0 // * 2

x*(x-3) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x )

x = 0

x in { 3, 0 }

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